In a wye system, the voltage between two phases will always be ______ times higher than the voltage between one phase and the neutral.

• A. 1.732 (√3)
• B. 0.577
• C. 2.0
• D. 1.0

Answer: (A)

In a wye system, the line-to-line voltage is the vector difference between two phase-to-neutral voltages. The phase voltages are equal in magnitude and 120 degrees apart, so the line-to-line voltage has magnitude V_LL = √(V^2 + V^2 − 2V^2 cos 120°) = √(3)·V. That means the voltage between two phases is √3 times the voltage between one phase and neutral (about 1.732 times higher). The correct factor is √3, matching approximately 1.732.